The number of solution$(s)$ of the equation $2^x = x^2$ is

  • A

    $1$

  • B

    $2$

  • C

    $3$

  • D

    $4$

Similar Questions

If $2 + i$ is a root of the equation ${x^3} - 5{x^2} + 9x - 5 = 0$, then the other roots are

Let $a, b, c, d$ be real numbers between $-5$ and $5$ such that  $|a|=\sqrt{4-\sqrt{5-a}},|b|=\sqrt{4+\sqrt{5-b}},|c|=\sqrt{4-\sqrt{5+c}}$ $|d|=\sqrt{4+\sqrt{5+d}}$ Then, the product $a b c d$ is

  • [KVPY 2017]

How many positive real numbers $x$ satisfy the equation $x^3-3|x|+2=0$ ?

  • [KVPY 2009]

The number of solutions for the equation ${x^2} - 5|x| + \,6 = 0$ is

Exact set of values of $a$ for which ${x^3}(x + 1) = 2(x + a)(x + 2a)$ is having four real solutions is