- Home
- Standard 11
- Mathematics
Trigonometrical Equations
hard
The number of solutions of the equation $1 + {\sin ^4}\,x = {\cos ^2}\,3x,x\,\in \,\left[ { - \frac{{5\pi }}{2},\frac{{5\pi }}{2}} \right]$ is
A
$3$
B
$4$
C
$5$
D
$7$
(JEE MAIN-2019)
Solution
$1\, + \,{\sin ^4}x\, = \,{\cos ^2}3x$
$\sin \,x\, = \,0$ and $\cos \,3x\, = 1$
$0,\,\,2\pi ,\, – \,2\pi ,\, – \,\pi ,\pi $
Standard 11
Mathematics