Trigonometrical Equations
hard

The number of solutions of the equation $1 + {\sin ^4}\,x = {\cos ^2}\,3x,x\,\in \,\left[ { - \frac{{5\pi }}{2},\frac{{5\pi }}{2}} \right]$ is

A

$3$

B

$4$

C

$5$

D

$7$

(JEE MAIN-2019)

Solution

$1\, + \,{\sin ^4}x\, = \,{\cos ^2}3x$

$\sin \,x\, = \,0$  and  $\cos \,3x\, = 1$

$0,\,\,2\pi ,\, – \,2\pi ,\, – \,\pi ,\pi $

Standard 11
Mathematics

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