The position of a particle is given by : over | vedclass

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Question

$\mathop L\limits^ 	o   = \mathop r\limits^ 	o   	imes \mathop p\limits^ 	o   = $ $\left| {\,\begin{array}{*{20}{c}}

Vedclass · Accepted Answer

$X$ - axis

Vedclass · Answer

$\mathop L\limits^ 	o   = \mathop r\limits^ 	o   	imes \mathop p\limits^ 	o   = $ $\left| {\,\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\,\,\hat k}\{1\,\,}&{\,2\,\,}&{ - 1}\{3\,\,}&{\,4\,\,}&{ - 2}\end{array}\,} ight|$ $ = 0\hat i - \hat j - 2\hat k =  - \hat j - 2\hat k$  and the X- axis is given by $i + 0\hat j + 0\hat k$

Dot product of these two vectors is zero $i.e.$ angular momentum is perpendicular to $X$ - axis.

The position of a particle is given by : $\overrightarrow {r\,} = (\hat i + 2\hat j - \hat k)$ and momentum $\overrightarrow P = (3\hat i + 4\hat j - 2\hat k)$. The angular momentum is perpendicular to

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