The position vector of a particle is vec r = | vedclass

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Question

(b) $\vec r = (a\cos \omega \,t)\hat i + (a\sin \omega \,t)\hat j$
$\vec v = \frac{{d\vec r}}{{dt}} = - a\omega \sin \omega \,t\,\hat i + a\omega \co

Vedclass · Accepted Answer

Perpendicular to the position vector

Vedclass · Answer

(b) $\vec r = (a\cos \omega \,t)\hat i + (a\sin \omega \,t)\hat j$
$\vec v = \frac{{d\vec r}}{{dt}} = - a\omega \sin \omega \,t\,\hat i + a\omega \cos \omega \,t\,\hat j$
As $\vec r.\vec v = 0$ therefore velocity of the particle is perpendicular to the position vector.

The position vector of a particle is $\vec r = (a\cos \omega t)\hat i + (a\sin \omega t)\hat j$. The velocity of the particle is

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