Potential energy of a particle oscillating along x- axis is given as U =20+ (x - 2)^2 where U is in

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5.Work, Energy, Power and Collision

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The potential energy of a particle oscillating along $x-$ axis is given as $U =20+ (x - 2)^2$ where $U$ is in $joules$ and $x$ in $meters$ . Total mechanical energy of the particle is $36 \,J$. Maximum kinetic energy of the particle is ............... $\mathrm{J}$

A

$24$

B

$36$

C

$16$

D

$20$

Solution

$U_{min} = 20\,J$ at $x = 2\,m$

$U_{min} + KE_{max} = TE$

$KE_{max} = 36 -20 = 16\, J$

Standard 11

Physics

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