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5.Work, Energy, Power and Collision
easy
The potential energy of a weight less spring compressed by a distance $ a $ is proportional to
A
$a$
B
${a^2}$
C
${a^{ - 2}}$
D
${a^0}$
Solution
(b)Potential energy of spring = $\frac{1}{2}K{x^2}$
$PE \propto {x^2}$$⇒$ $PE \propto {a^2}$
Standard 11
Physics
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