Gujarati
5.Work, Energy, Power and Collision
easy

The potential energy of a weight less spring compressed by a distance $ a $ is proportional to

A

$a$

B

${a^2}$

C

${a^{ - 2}}$

D

${a^0}$

Solution

(b)Potential energy of spring = $\frac{1}{2}K{x^2}$
 $PE \propto {x^2}$$⇒$ $PE \propto {a^2}$

Standard 11
Physics

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