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2. Electric Potential and Capacitance
easy
The potential to which a conductor is raised, depends on
A
The amount of charge
B
Geometry and size of the conductor
C
Both $(a)$ and $(b)$
D
Only on $(a)$
Solution
(c) $V = Q/C$
$Q$ $=$ the amount of charge
$C$ $=$ capacitance which depends on geometry and size of conductor.
Standard 12
Physics
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