The probability that a leap year will have $53$ Fridays or $53$ Saturdays is
The probability that a leap year will have $53$ Fridays or $53$ Saturdays is
- A
$\frac{2}{7}$
- B
$\frac{3}{7}$
- C
$\frac{4}{7}$
- D
$\frac{1}{7}$
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- [AIEEE 2003]
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