The radius of a nucleus is given by $r_0 A^{1 / 3}$, where $r_0=1.3 \times 10^{-15} \,m$ and $A$ is the mass number of the nucleus. The lead nucleus has $A=206$. The electrostatic force between two protons in this nucleus is approximately ................ $N$

  • [KVPY 2016]
  • A

    $10^2$

  • B

    $10^7$

  • C

    $10^{12}$

  • D

    $10^{17}$

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