The radius of a nucleus of mass number 64 is | vedclass

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Question

$\mathrm{R}=\mathrm{R}_0 \mathrm{~A}^{1 / 3}$

$\mathrm{R}^3 \propto \mathrm{A}$

$\left(\frac{4.8}{4}\right)^3=\frac{64}{\mathrm{~A}}$

$=\frac

Vedclass · Accepted Answer

$27$

Vedclass · Answer

$\mathrm{R}=\mathrm{R}_0 \mathrm{~A}^{1 / 3}$

$\mathrm{R}^3 \propto \mathrm{A}$

$\left(\frac{4.8}{4}ight)^3=\frac{64}{\mathrm{~A}}$

$=\frac{64}{\mathrm{~A}}=(1.2)^3$

$\frac{64}{\mathrm{~A}}=1.44 	imes 1.2$

$\mathrm{~A}=\frac{64}{1.44 	imes 1.2}=\frac{1000}{\mathrm{x}}$

$\mathrm{x}=\frac{144 	imes 12}{64}=27$

The radius of a nucleus of mass number $64$ is $4.8$ fermi. Then the mass number of another nucleus having radius of $4$ fermi is $\frac{1000}{x}$, where $x$ is______.

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