Radius of two metallic spheres A and B are {r₁} and {r₂} respectively ({r₁}

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1. Electric Charges and Fields

easy

The radius of two metallic spheres $A$ and $B$ are ${r_1}$ and ${r_2}$ respectively $({r_1} > {r_2})$. They are connected by a thin wire and the system is given a certain charge. The charge will be greater

On the surface of the sphere $B$

On the surface of the sphere $A$

Equal on both

Zero on both

Solution

(b) After connection of wire, potential becomes equal
$\frac{{{Q_1}}}{{{r_1}}} = \frac{{{Q_2}}}{{{r_2}}}$ $==>$ $\frac{{{Q_1}}}{{{Q_2}}} = \frac{{{r_1}}}{{{r_2}}}$ when $r_1$ $>$ $r_2$, then ${Q_1} > {Q_2}$

Standard 12

Physics

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The radius of two metallic spheres $A$ and $B$ are ${r_1}$ and ${r_2}$ respectively $({r_1} > {r_2})$. They are connected by a thin wire and the system is given a certain charge. The charge will be greater

Solution

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