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1.Relation and Function
normal
The range of values of the function $f\left( x \right) = \frac{1}{{2 - 3\sin x}}$ is
A
$\left[ { - 1,\frac{1}{5}} \right]$
B
$\left[ { - 1,5} \right]$
C
$\left( { - \infty , - 1} \right] \cup \left[ {\frac{1}{5},\infty } \right)$
D
$\left( { - \infty ,\frac{1}{5}} \right] \cup \left[ {1,\infty } \right)$
Solution
$-3 \leq 3 \sin x \leq 3$
$-1 \leq 2-3 \sin x \leq 5$
$\frac{1}{2-3 \sin x} \in(-\infty,-1] \cup\left[\frac{1}{5}, \infty\right)$
Standard 12
Mathematics
