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10-2.Transmission of Heat
hard
The rate of heat flow through the cross-section of the rod shown in figure is ($T_2 > T_1$ and thermal conductivity of the material of the rod is $K$)

A
$\frac{{K\pi {r_1}{r_2}\left( {{T_2} - {T_1}} \right)}}{L}$
B
$\frac{{K\pi {{\left( {{r_1} + {r_2}} \right)}^2}\left( {{T_2} - {T_1}} \right)}}{{4L}}$
C
$\frac{{K\pi {{\left( {{r_1} + {r_2}} \right)}^2}\left( {{T_2} - {T_1}} \right)}}{{L}}$
D
$\frac{{K\pi {{\left( {{r_1} + {r_2}} \right)}^2}\left( {{T_2} - {T_1}} \right)}}{{2L}}$
Solution
${r_{eff}} = \sqrt {{r_1}{r_2}} $
$\frac{{dQ}}{{dt}} = \frac{{KA\left( {{T_2} – {T_1}} \right)}}{L} = \frac{{K\pi {r_1}{r_2}\left( {{T_2} – {T_1}} \right)}}{L}$
Standard 11
Physics
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