The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to

  • A

    The ratio of magnetic permeability to the electric susceptibility of vacuum

  • B

    Unity

  • C

    The speed of light in vacuum

  • D

    Reciprocal of speed of light in vacuum

Similar Questions

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $2.0 \times 10^{10}\; Hz$ and amplitude $48\; Vm ^{-1}$

$(a)$ What is the wavelength of the wave?

$(b)$ What is the amplitude of the oscillating magnetic field?

$(c)$ Show that the average energy density of the $E$ field equals the average energy density of the $B$ field. $\left[c=3 \times 10^{8} \;m s ^{-1} .\right]$

Consider an electromagnetic wave propagating in vacuum . Choose the correct statement

  • [JEE MAIN 2016]

Even though an electric field $E$ exerts a force $qE$ on a charged particle yet the electric field of an $EM$ wave does not contribute to the radiation pressure (but transfers energy). Explain.

A charged particle oscillates about its mean equilibrium position with a frequency of $10^9 \;Hz$. What is the frequency of the electromagnetic waves produced by the oscillator?

Assume a bulb of efficiency $2.5\%$ as a point source. The peak values of electric field produced by the radiation coming from a $100\, W$ bulb at a distance of $3\, m$ is respectively.....$V\,{m^{ - 1}}$