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8.Electromagnetic waves
easy
The ratio of average electric energy density and total average energy density of electromagnetic wave is:
A
$2$
B
$1$
C
$3$
D
$\frac{1}{2}$
(JEE MAIN-2023)
Solution
$\left\langle u _{ E }\right\rangle=\left\langle u _{ B }\right\rangle=\frac{1}{2}\left\langle u _{\text {total }}\right\rangle$
So $\frac{\left\langle u_E\right\rangle}{\left\langle u_{\text {total }}\right\rangle}=\frac{1}{2}$
Standard 12
Physics
