The resultant of these forces overrightarrow{ | vedclass

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Question

$\hat{F}_{x}=\left(10 	imes \frac{\sqrt{3}}{2}+20\left(\frac{1}{2}ight)+20\left(\frac{1}{\sqrt{2}}ight)-15\left(\frac{1}{\sqrt{2}}ight)-15\left

Vedclass · Accepted Answer

$9.25 \hat{{i}}+5 \hat{{j}}$

Vedclass · Answer

$\hat{F}_{x}=\left(10 	imes \frac{\sqrt{3}}{2}+20\left(\frac{1}{2}ight)+20\left(\frac{1}{\sqrt{2}}ight)-15\left(\frac{1}{\sqrt{2}}ight)-15\left(\frac{\sqrt{3}}{2}ight)ight) \hat{i}$

$=9.25 \hat{i}$

$\vec{F}_{y}=\left(15\left(\frac{1}{2}ight)+20\left(\frac{\sqrt{3}}{2}ight)+10\left(\frac{1}{2}ight)-15\left(\frac{1}{\sqrt{2}}ight)-20\left(\frac{1}{\sqrt{2}}ight)ight) \hat{j}$

$=5 \hat{j}$

The resultant of these forces $\overrightarrow{O P}, \overrightarrow{O Q}, \overrightarrow{O R}, \overrightarrow{O S}$ and $\overrightarrow{{OT}}$ is approximately $\ldots \ldots {N}$.

[Take $\sqrt{3}=1.7, \sqrt{2}=1.4$ Given $\hat{{i}}$ and $\hat{{j}}$ unit vectors along ${x}, {y}$ axis $]$

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The resultant of these forces $\overrightarrow{O P}, \overrightarrow{O Q}, \overrightarrow{O R}, \overrightarrow{O S}$ and $\overrightarrow{{OT}}$ is approximately $\ldots \ldots {N}$. [Take $\sqrt{3}=1.7, \sqrt{2}=1.4$ Given $\hat{{i}}$ and $\hat{{j}}$ unit vectors along ${x}, {y}$ axis $]$