The roots of the equation {x^4} - 2{x^3} + x | vedclass

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Question

(a) Given equation is ${x^4} - 2{x^3} + x - 380 = 0$

Using remainder theorem we get

$(x - 5)\,(x + 4)({x^2} - x + 19) = 0$

$x - 5 = 0$, $x -

Vedclass · Accepted Answer

$5, - 4,\frac{{1 \pm 5\sqrt { - 3} }}{2}$

Vedclass · Answer

(a) Given equation is ${x^4} - 2{x^3} + x - 380 = 0$

Using remainder theorem we get

$(x - 5)\,(x + 4)({x^2} - x + 19) = 0$

$x - 5 = 0$, $x - 4 = 0$ and ${x^2} - x + 19 = 0$

$x = 5$, $x = - 4$ and $x = \frac{{ - 1 \pm 5\sqrt { - 3} }}{2}$.

The roots of the equation ${x^4} - 2{x^3} + x = 380$ are

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