The roots of the equation ${x^4} - 2{x^3} + x = 380$ are
$5, - 4,\frac{{1 \pm 5\sqrt { - 3} }}{2}$
$ - 5,4, - \frac{{1 \pm 5\sqrt - 3}}{2}$
$5,4,\frac{{ - 1 \pm 5\sqrt - 3}}{2}$
$ - 5, - 4,\frac{{1 \pm 5\sqrt - 3}}{2}$
If $\alpha,\beta,\gamma, \delta$ are the roots of $x^4-100x^3+2x^2+4x+10 = 0$ then $\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}+\frac{1}{\delta}$ is equal to :-
The equation${e^x} - x - 1 = 0$ has
If the quadratic equation ${x^2} + \left( {2 - \tan \theta } \right)x - \left( {1 + \tan \theta } \right) = 0$ has $2$ integral roots, then sum of all possible values of $\theta $ in interval $(0, 2\pi )$ is $k\pi $, then $k$ equals
Let $a, b, c$ be non-zero real numbers such that $a+b+c=0$, let $q=a^2+b^2+c^2$ and $r=a^4+b^4+c^4$. Then,
Leela and Madan pooled their music $CD's$ and sold them. They got as many rupees for each $CD$ as the total number of $CD's$ they sold. They share the money as follows: Leela first takes $10$ rupees, then Madan takes $10$ rupees and they continue taking $10$ rupees alternately till Madan is left out with less than $10$ rupees to take. Find the amount that is left out for Madan at the end, with justification.