Set A = { x:x ∈ R,,{x^2} = 16 and 2x = 6} equals

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1.Set Theory

easy

The set $A = \{ x:x \in R,\,{x^2} = 16$ and $2x = 6\} $ equals

A

$\phi $

B

$\{14, 3, 4\}$

C

$\{3\}$

D

$\{4\}$

Solution

(a) ${x^2} = 16$ ==> $x = \pm 4$

$2x = 6$ ==> $x = 3$

There is no value of $x$ which satisfies both the above equations. Thus, $A = \phi $.

Standard 11

Mathematics

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