The solution of the equation ${\log _7}{\log _5}$ $(\sqrt {{x^2} + 5 + x} ) = 0$
$x = 2$
$x = 3$
$x = 4$
$x = - 2$
Let $a=3 \sqrt{2}$ and $b=\frac{1}{5^{\frac{1}{6}} \sqrt{6}}$. If $x, y \in R$ are such that $3 x+2 y=\log _a(18)^{\frac{5}{4}} \text { and }$ $2 x-y=\log _b(\sqrt{1080}),$ then $4 x+5 y$ is equal to. . . .
The number ${\log _{20}}3$ lies in
Solution set of inequality ${\log _{10}}({x^2} - 2x - 2) \le 0$ is
The value of $(0.16)^{\log _{2.5}\left(\frac{1}{3}+\frac{1}{3^{2}}+\frac{1}{3^{3}}+\ldots . to \infty\right)}$ is equal to
If $\log x:\log y:\log z = (y - z)\,:\,(z - x):(x - y)$ then