The solution of the equation ${\log _7}{\log _5}$ $(\sqrt {{x^2} + 5 + x} ) = 0$
The solution of the equation ${\log _7}{\log _5}$ $(\sqrt {{x^2} + 5 + x} ) = 0$
- A
$x = 2$
- B
$x = 3$
- C
$x = 4$
- D
$x = - 2$
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- [JEE MAIN 2020]
If ${1 \over 2} \le {\log _{0.1}}x \le 2$ then
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