$7\log \left( {{{16} \over {15}}} \right) + 5\log \left( {{{25} \over {24}}} \right) + 3\log \left( {{{81} \over {80}}} \right)$ is equal to

  • A

    $0$

  • B

    $1$

  • C

    $\log 2$

  • D

    $\log 3$

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