Let a=3 sqrt{2} and b=frac{1}{5^{frac{1}{6}} | vedclass

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Question

$3 x+2 y=\log _{3 \sqrt{2}}(3 \sqrt{2})^{\frac{5}{2}}=\frac{5}{2}$

$\Rightarrow \quad 6 x+4 y=5$     $. . . (1)$

$2 x - y =\log _

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$8$

Vedclass · Answer

$3 x+2 y=\log _{3 \sqrt{2}}(3 \sqrt{2})^{\frac{5}{2}}=\frac{5}{2}$

$\Rightarrow \quad 6 x+4 y=5$     $. . . (1)$

$2 x - y =\log _{\frac{1}{5^{1 / 6} \sqrt{6}}}\left(5^{\frac{1}{6}} \sqrt{6}ight)^3=-3$

$\Rightarrow \quad 2 x - y =-3$      $. . . (2)$

$	ext { equation (1) - (2) }$

$\Rightarrow \quad 4 x+5 y=8$

Let $a=3 \sqrt{2}$ and $b=\frac{1}{5^{\frac{1}{6}} \sqrt{6}}$. If $x, y \in R$ are such that $3 x+2 y=\log _a(18)^{\frac{5}{4}} \text { and }$ $2 x-y=\log _b(\sqrt{1080}),$ then $4 x+5 y$ is equal to. . . .

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