If $\left(\frac{x}{3}+1, y-\frac{2}{3}\right)=\left(\frac{5}{3}, \frac{1}{3}\right),$ find the values of $x$ and $y$
It is given that $\left(\frac{x}{3}+1, y-\frac{2}{3}\right)=\left(\frac{5}{3}, \frac{1}{3}\right)$
Since the ordered pairs are equal, the corresponding elements will also be equal.
Therefore, $\frac{x}{3}+1=\frac{5}{3}$ and $y-\frac{2}{3}=\frac{1}{3}$
$\frac{x}{3}+1=\frac{5}{3}$
$\Rightarrow \frac{x}{3}=\frac{5}{3}-1 \quad y-\frac{2}{3}=\frac{1}{3}$
$\Rightarrow \frac{x}{3}=\frac{2}{3} \Rightarrow y=\frac{1}{3}+\frac{2}{3}$
$\Rightarrow x=2 \Rightarrow y=1$
$\therefore x=2$ and $y=1$
If $A = \{1, 2, 4\}, B = \{2, 4, 5\}, C = \{2, 5\},$ then $(A -B) × (B -C)$ is
Let $A=\{1,2\}, B=\{1,2,3,4\}, C=\{5,6\}$ and $D=\{5,6,7,8\} .$ Verify that
$A \times C$ is a subset of $B \times D$
$A = \{1, 2, 3\}$ and $B = \{3, 8\}$, then $(A \cup B) × (A \cap B)$ is
If $G =\{7,8\}$ and $H =\{5,4,2\},$ find $G \times H$ and $H \times G$.
Let $A=\{1,2\}, B=\{1,2,3,4\}, C=\{5,6\}$ and $D=\{5,6,7,8\} .$ Verify that
$A \times(B \cap C)=(A \times B) \cap(A \times C)$