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- Standard 12
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3 and 4 .Determinants and Matrices
medium
The solutions of the equation $\left| {\,\begin{array}{*{20}{c}}x&2&{ - 1}\\2&5&x\\{ - 1}&2&x\end{array}\,} \right| = 0$ are
A
$3,\,\, - 1$
B
$ - 3,\,\,1$
C
$3, 1$
D
$ - 3,\,\, - 1$
Solution
(a) $\left| {\,\begin{array}{*{20}{c}}x&2&{ – 1}\\2&5&x\\{ – 1}&2&x\end{array}\,} \right| = 0$
==>$x(5x – 2x) – 2(2x + x) – 1(4 + 5) = 0$
==> $3{x^2} – 6x – 9 = 0$,
==> ${x^2} – 2x – 3 = 0$,
==> $(x + 1)(x – 3) = 0$
$ \Rightarrow x = – 1,\,3$.
Standard 12
Mathematics