3 and 4 .Determinants and Matrices
medium

The solutions of the equation $\left| {\,\begin{array}{*{20}{c}}x&2&{ - 1}\\2&5&x\\{ - 1}&2&x\end{array}\,} \right| = 0$ are

A

$3,\,\, - 1$

B

$ - 3,\,\,1$

C

$3, 1$

D

$ - 3,\,\, - 1$

Solution

(a) $\left| {\,\begin{array}{*{20}{c}}x&2&{ – 1}\\2&5&x\\{ – 1}&2&x\end{array}\,} \right| = 0$

==>$x(5x – 2x) – 2(2x + x) – 1(4 + 5) = 0$

==> $3{x^2} – 6x – 9 = 0$,

==> ${x^2} – 2x – 3 = 0$,

==> $(x + 1)(x – 3) = 0$

$ \Rightarrow x = – 1,\,3$.

Standard 12
Mathematics

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