Gujarati
10-1.Circle and System of Circles
easy

The square of the length of the tangent from $(3, -4)$ on the circle ${x^2} + {y^2} - 4x - 6y + 3 = 0$ is

A

$20$

B

$30$

C

$40$

D

$50$

Solution

(c) Length of tangent

= $\sqrt {{3^2} + {{( – 4)}^2} – 4\,(3)\, – 6\,( – 4) + 3} $

$ = \sqrt {40} $

$\therefore $ Square of length of tangent $ = 40$.

Standard 11
Mathematics

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