- Home
- Standard 11
- Mathematics
10-1.Circle and System of Circles
easy
The square of the length of the tangent from $(3, -4)$ on the circle ${x^2} + {y^2} - 4x - 6y + 3 = 0$ is
A
$20$
B
$30$
C
$40$
D
$50$
Solution
(c) Length of tangent
= $\sqrt {{3^2} + {{( – 4)}^2} – 4\,(3)\, – 6\,( – 4) + 3} $
$ = \sqrt {40} $
$\therefore $ Square of length of tangent $ = 40$.
Standard 11
Mathematics