The statement $[(p \wedge  q) \rightarrow p] \rightarrow (q \wedge  \sim q)$ is

Consider the following two propositions:

$P_1: \sim( p \rightarrow \sim q )$

$P_2:( p \wedge \sim q ) \wedge((\sim p ) \vee q )$

If the proposition $p \rightarrow((\sim p ) \vee q )$ is evaluated as $FALSE$, then

The number of choices of $\Delta \in\{\wedge, \vee, \Rightarrow, \Leftrightarrow\}$, such that $( p \Delta q ) \Rightarrow(( p \Delta \sim q ) \vee((\sim p ) \Delta q ))$ is a tautology, is

The statement $p \rightarrow  (q \rightarrow p)$  is equivalent to

Let,$p$ : Ramesh listens to music.

$q :$ Ramesh is out of his village

$r :$ It is Sunday

$s :$ It is Saturday

Then the statement "Ramesh listens to music only if he is in his village and it is Sunday or Saturday"can be expressed as.

Negation of the statement $(p \vee r) \Rightarrow(q \vee r)$ is :