The conditional $(p \wedge q) \Rightarrow p$ is :-
A tautology
A fallacy i.e., contradiction
Neither tautology nor fallacy
None of these
The compound statement $(\sim( P \wedge Q )) \vee((\sim P ) \wedge Q ) \Rightarrow((\sim P ) \wedge(\sim Q ))$ is equivalent to
Which one of the following is a tautology ?
$\left( { \sim \left( {p \vee q} \right)} \right) \vee \left( { \sim p \wedge q} \right)$ is logically equivalent to
The statement $\sim(p\leftrightarrow \sim q)$ is :
The statement $(p \wedge(\sim q) \vee((\sim p) \wedge q) \vee((\sim p) \wedge(\sim q))$ is equivalent to