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Mathematical Reasoning
normal
The conditional $(p \wedge q) \Rightarrow p$ is :-
A
A tautology
B
A fallacy i.e., contradiction
C
Neither tautology nor fallacy
D
None of these
Solution
| $p$ | $q$ | ${p \wedge q}$ | ${\left( {p \wedge q} \right) \Rightarrow p}$ |
| $T$ | $T$ | $T$ | $T$ |
| $T$ | $F$ | $F$ | $T$ |
| $F$ | $T$ | $F$ | $T$ |
| $F$ | $F$ | $F$ | $T$ |
${\therefore \left( {p \wedge q} \right) \Rightarrow p}$ is a tautology.
Standard 11
Mathematics
