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Mathematical Reasoning
normal
વિધાન $p → (p \leftrightarrow q)$ =
A
$(p → q) \vee (q → p)$
B
$(p → q) \wedge (q →p)$
C
$(q→ p) → (p → q)$
D
$(q → p) \leftrightarrow (p →q)$
Solution
Here statements $p → (p \leftrightarrow q)$ and $(q → p) → (p → q) $ both are false only when $p$ is true and $q$ is false otherwise they are true.
Standard 11
Mathematics
