The sum of the first and third term of an ari | vedclass

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Question

(c) Let first $3$ terms be $a - d,a\,\,$and $a + d$

Now $(a - d) + (a + d) = 12$

$ \Rightarrow $$2a = 12$

$ \Rightarrow $ $a = 6$ and $(a - d

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(c) Let first $3$ terms be $a - d,a\,\,$and $a + d$

Now $(a - d) + (a + d) = 12$

$ \Rightarrow $$2a = 12$

$ \Rightarrow $ $a = 6$ and $(a - d)a = 24$

$&rArr;$ $6(6 - d) = 24$

$&rArr;$  $d = 2$

First term = $a - d = 6 - 2 = 4$.

The sum of the first and third term of an arithmetic progression is $12$ and the product of first and second term is $24$, then first term is

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