The sun radiates energy in all directions. Th | vedclass

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Question

(d) Energy radiated $ = 1.4\;kW/{m^2}$

$ = 1.4\;kJ/\sec \;{m^2} = \frac{{1.4\;kJ}}{{\frac{1}{{86400}}day\;{m^2}}} = \frac{{1.4 	imes 86400}}{{day\

Vedclass · Accepted Answer

$3.8 	imes {10^{14}}kg$

Vedclass · Answer

(d) Energy radiated $ = 1.4\;kW/{m^2}$

$ = 1.4\;kJ/\sec \;{m^2} = \frac{{1.4\;kJ}}{{\frac{1}{{86400}}day\;{m^2}}} = \frac{{1.4 	imes 86400}}{{day\;{m^2}}}$

Total energy radiated$/$day

$ = \frac{{4\pi 	imes {{(1.5 	imes {{10}^{11}})}^2} 	imes 1.4 	imes 86400}}{1}\frac{{kJ}}{{day}} = E$

$	herefore E = m{c^2} \Rightarrow m = \frac{E}{{{c^2}}}$

$ = \frac{{4\pi {{(1.5 	imes {{10}^{11}})}^2} 	imes 1.4 	imes 86400}}{{{{(3 	imes {{10}^8})}^2}}} = 3.8 	imes {10^{14}}kg$.

The sun radiates energy in all directions. The average radiations received on the earth surface from the sun is $1.4\;kilowatt/{m^2}$.The average earth- sun distance is $1.5 \times {10^{11}}metres$. The mass lost by the sun per day is($1$ day $= 86400$ seconds)

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