Surface tension of a liquid is 70,dyne/cm . In MKS system its value is

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1.Units, Dimensions and Measurement

medium

The surface tension of a liquid is $70\,dyne/cm$. In $MKS$ system its value is

A$70N/m$

B$7 \times {10^{ - 2}}\,N/m$

C$7 \times {10^3}\,N/m$

D$7 \times {10^2}\,N/m$

Solution

(b) $1$ dyne $ = {10^{ – 5}}$ Newton, $1\,cm = {10^{ – 2}}m$
$70\,\frac{{dyne}}{{cm}} = \frac{{70 \times {{10}^{ – 5}}}}{{{{10}^{ – 2}}}}\;\frac{N}{m}$
= $7 \times {10^{ – 2}}N/m$.

Standard 11

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(JEE MAIN-2023)

Given below are two statements: One is labelled as Assertion $(A)$ and other is labelled as Reason $(R)$.
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(JEE MAIN-2022)

The surface tension of a liquid is $70\,dyne/cm$. In $MKS$ system its value is

Solution

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