The surface tension of a liquid is 70,dyne/cm | vedclass

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Question

(b) $1$ dyne $ = {10^{ - 5}}$ Newton, $1\,cm = {10^{ - 2}}m$

$70\,\frac{{dyne}}{{cm}} = \frac{{70 	imes {{10}^{ - 5}}}}{{{{10}^{ - 2}}}}\;\frac{N}

Vedclass · Accepted Answer

$7 	imes {10^{ - 2}}\,N/m$

Vedclass · Answer

(b) $1$ dyne $ = {10^{ - 5}}$ Newton, $1\,cm = {10^{ - 2}}m$

$70\,\frac{{dyne}}{{cm}} = \frac{{70 	imes {{10}^{ - 5}}}}{{{{10}^{ - 2}}}}\;\frac{N}{m}$

= $7 	imes {10^{ - 2}}N/m$.

The surface tension of a liquid is $70\,dyne/cm$. In $MKS$ system its value is

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