The temperature of a body falls from $62^oC\, to\, 50^oC$ in $10$ minutes. If the temperature of the surroundings is $26^oC$, the temperature in next $10$ minutes will become ...... $^oC$
$42$
$40$
$56$
$55$
A body cools in a surrounding which is at a constant temperature of ${\theta _0}$. Assume that it obeys Newton's law of cooling. Its temperature $\theta $ is plotted against time $t$ . Tangents are drawn to the curve at the points $P(\theta = {\theta _1})$ and $Q(\theta = {\theta _2})$. These tangents meet the time axis at angles of ${\varphi _2}$and ${\varphi _1}$, as shown
The rates of cooling of two different liquids put in exactly similar calorimeters and kept in identical surroundings are the same if
A body takes $10$ minutes to cool down from $62^o C$ to $50^o C$. If the temperature of surrounding is $26^o C$ then in the next $10$ minutes temperature of the body will be ......... $^oC$
A sphere at temperature $600\,K$ is placed in an environment of temperature is $200\,K$ . Its cooling rate is $H$ . If its temperature reduced to $400\,K$ then cooling rate in same environment will become
It takes $10$ minutes to cool a liquid from $61^oC$ to $59^oC$. If room temperature is $30^oC$ then time taken in cooling from $51^oC$ to $49^oC$ is ....... $\min$