The temperature of a hypothetical gas increas | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) $T{V^{\gamma - 1}}$= constant
$	herefore  \frac{{{T_1}}}{{{T_2}}} = {\left( {\frac{{{V_2}}}{{{V_1}}}} ight)^{\gamma - 1}}$or ${\left

Vedclass · Accepted Answer

$P{V^{3/2}}$= constant

Vedclass · Answer

(a) $T{V^{\gamma - 1}}$= constant
$	herefore  \frac{{{T_1}}}{{{T_2}}} = {\left( {\frac{{{V_2}}}{{{V_1}}}} ight)^{\gamma - 1}}$or ${\left( {\frac{1}{2}} ight)^{\gamma - 1}} = \sqrt {\frac{1}{2}} $
 $	herefore \gamma - 1 = \frac{1}{2}$or $\gamma = \frac{3}{2}$

$P{V^{3/2}}$= constant

The temperature of a hypothetical gas increases to $\sqrt 2 $ times when compressed adiabatically to half the volume. Its equation can be written as

Similar Questions

A balloon filled with helium $\left(32^{\circ} C \right.$ and $1.7\; atm$.) bursts. Immediately afterwards the expansion of helium can be considered as

Check the statement are trrue or false :

$1.$ The change in internal energy $\Delta U = 0$ in a cyclic process.

$2.$ In an adiabatic process temperature remains constant.

$3.$ The internal energy of a system during isothermal process decreases.

In the following figure, four curves $A, B, C$ and $D$ are shown. The curves are

The initial pressure and volume of an ideal gas are $P_0$ and $V_0$. The final pressure of the gas when the gas is suddenly compressed to volume $\frac{ V _0}{4}$ will be (Given $\gamma=$ ratio of specific heats at constant pressure and at constant volume)

In adiabatic expansion