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10-2.Transmission of Heat
hard
The temperature of a liquid drops from $365K$ to $361 K$ in $2$ minutes. Find the time during which temperature of the liquid drops from $344\;K$ to $342K$. Temperature of room is $293\;K$ ....... $\sec$
A
$84$
B
$72$
C
$66$
D
$60$
Solution
(a) $\frac{{365 – 361}}{2}$$ = K\left[ {\frac{{365 + 361}}{2} – 293} \right]= 70 K$
==> $K = \frac{1}{{35}}$
Again $\frac{{344 – 342}}{t} = \frac{1}{{35}}\left[ {\frac{{344 – 342}}{2} – 293} \right] = \frac{{10}}{7}$
==> $t = \frac{{14}}{{10}}$min = $\frac{{14}}{{10}} \times 60 = 84$sec.
Standard 11
Physics
