The term independent of x in {left( {2x - fra | vedclass

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Question

(d) We have ${(x)^{12 - r}}{\left( {\frac{1}{{{x^2}}}} \right)^r} = {x^0}\,\, \Rightarrow {x^{12 - 3r}} = {x^0} \Rightarrow r = 4$

Hence the requir

Vedclass · Accepted Answer

$7920$

Vedclass · Answer

(d) We have ${(x)^{12 - r}}{\left( {\frac{1}{{{x^2}}}} \right)^r} = {x^0}\,\, \Rightarrow {x^{12 - 3r}} = {x^0} \Rightarrow r = 4$

Hence the required term is $^{12}{C_4}{2^8}{\left( { - \frac{1}{2}} \right)^4} = 7920$.

The term independent of $x$ in ${\left( {2x - \frac{1}{{2{x^2}}}} \right)^{12}}$is

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