- Home
- Standard 11
- Mathematics
7.Binomial Theorem
easy
The term independent of $x$ in the expansion of ${\left( {2x - \frac{3}{x}} \right)^6}$ is
A
$4320$
B
$216$
C
$-216$
D
$-4320$
Solution
(d) ${T_{r + 1}} = \,{}^6{C_r}{(2x)^{6 – r}}{\left( { – \frac{3}{x}} \right)^r}$
= ${}^6{C_r}{(2)^{6 – r}}{( – 3)^r}{(x)^{6 – 2r}}$
For term independent of $x$, $6 -2r = 0$ i.e. $r = 3$
$\therefore {T_4} = {\,^6}{C_3}\,{2^{6 – 3}}{( – 3)^3}$ $= -4320$.
Standard 11
Mathematics