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4.Chemical Bonding and Molecular Structure
hard
The total number of electrons in all bonding molecular orbitals of $O_{2}^{2-}$ is $....\,.$
(Round off to the Nearest Integer).
A
$5$
B
$10$
C
$15$
D
$20$
(JEE MAIN-2021)
Solution
$\sigma 1 \mathrm{~s}^{2} \sigma 1^* \mathrm{~s}^{2} \sigma 2 \mathrm{~s}^{2} \sigma 2^* \mathrm{~s}^{2} \sigma 2 \mathrm{p}_{z}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}$
$\pi 2^* \mathrm{p}_{\mathrm{x}}^{2}=\pi 2^* \mathrm{p}_{\mathrm{y}}^{2}$
Standard 11
Chemistry
Similar Questions
Match List $I$ with List $II$ :
|
List $I$ (Molecule Species) |
List $I$ ( Property Shape ) |
| $A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ | $I$ Paramagnetic |
| $B$ $NO$ | $II$ Diamagnetic |
| $C$ $\mathrm{NO}_2^{-}$ | $III$ Tetrahedral |
| $D$ $\mathrm{I}_3^{-}$ | $IV$ Linear |
Choose the correct answer from the options given below :
