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4.Chemical Bonding and Molecular Structure
hard
The total number of electrons in all bonding molecular orbitals of $O_{2}^{2-}$ is $....\,.$
(Round off to the Nearest Integer).
A
$5$
B
$10$
C
$15$
D
$20$
(JEE MAIN-2021)
Solution
$\sigma 1 \mathrm{~s}^{2} \sigma 1^* \mathrm{~s}^{2} \sigma 2 \mathrm{~s}^{2} \sigma 2^* \mathrm{~s}^{2} \sigma 2 \mathrm{p}_{z}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}$
$\pi 2^* \mathrm{p}_{\mathrm{x}}^{2}=\pi 2^* \mathrm{p}_{\mathrm{y}}^{2}$
Standard 11
Chemistry
