Total number of three-digit numbers, with one digit repeated exactly two times, is

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6.Permutation and Combination

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The total number of three-digit numbers, with one digit repeated exactly two times, is

A

$256$

B

$289$

C

$243$

D

$237$

(JEE MAIN-2022)

Solution

If 0 taken twice then ways $=9$

If 0 taken once then ${ }^{9} C _{1} \times 2=18$

If 0 not taken then ${ }^{9} C _{1}{ }^{8} C _{1} \cdot 3=216$

Total $=243$

Standard 11

Mathematics

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