$\sqrt 3 \, cosec\, 20^o - sec\, 20^o $ =
$\sqrt 3 \, cosec\, 20^o - sec\, 20^o $ =
- A
$2$
- B
$\frac{{2\,\sin \,20^\circ }}{{\sin \,40^\circ }}$
- C
$4$
- D
$\frac{{4\,\sin \,20^\circ }}{{\sin \,40^\circ }}$
Similar Questions
જો $\sin \theta + \sin 2\theta + \sin 3\theta = \sin \alpha $અને $\cos \theta + \cos 2\theta + \cos 3\theta = \cos \alpha $, તો $\theta$ મેળવો.
જો $\sin \theta + \sin 2\theta + \sin 3\theta = \sin \alpha $અને $\cos \theta + \cos 2\theta + \cos 3\theta = \cos \alpha $, તો $\theta$ મેળવો.
$\frac{{\sqrt 2 - \sin \alpha - \cos \alpha }}{{\sin \alpha - \cos \alpha }} = $
$\frac{{\sqrt 2 - \sin \alpha - \cos \alpha }}{{\sin \alpha - \cos \alpha }} = $
જો $\tan A = \frac{{1 - \cos B}}{{\sin B}},$ હોય તો $\tan 2A$ અને $\tan B$ નો સંબંધ મેળવો..
જો $\tan A = \frac{{1 - \cos B}}{{\sin B}},$ હોય તો $\tan 2A$ અને $\tan B$ નો સંબંધ મેળવો..
- [IIT 1983]
જો $\alpha + \beta - \gamma = \pi ,$ તો ${\sin ^2}\alpha + {\sin ^2}\beta - {\sin ^2}\gamma = $
જો $\alpha + \beta - \gamma = \pi ,$ તો ${\sin ^2}\alpha + {\sin ^2}\beta - {\sin ^2}\gamma = $
- [IIT 1980]
$\cos \,\frac{\pi }{7}\,\cos \,\frac{{2\pi }}{7}\,\cos \,\frac{{3\pi }}{7}$ =
$\cos \,\frac{\pi }{7}\,\cos \,\frac{{2\pi }}{7}\,\cos \,\frac{{3\pi }}{7}$ =