$[1 - sin (3\pi - \alpha ) + cos (3\pi + \alpha )]$ $\left[ {1\,\, - \,\,\sin \,\left( {\frac{{3\,\pi }}{2}\,\, - \,\,\alpha } \right)\,\, + \,\,\cos \,\left( {\frac{{5\,\pi }}{2}\,\, - \,\,\alpha } \right)} \right]$ = 

  • A

    $sin \,2\alpha$

  • B

    $- sin\, 2\alpha$

  • C

    $1 - sin\, 2\alpha$

  • D

    $1 + sin\, 2\alpha$

Similar Questions

${\cos ^2}\,{10^o}\,\, - \,\cos \,\,{10^o}\,\cos \,\,{50^o}\, + \,{\cos ^2}\,{50^o}$ ની કિમત ..... થાય.

  • [JEE MAIN 2019]

જો $\cos x + \cos y + \cos \alpha = 0$ અને $\sin x + \sin y + \sin \alpha = 0,$ તો $\cot \,\left( {\frac{{x + y}}{2}} \right) = $

જો $\sin A + \cos A = \sqrt 2 ,$ તો ${\cos ^2}A = $

જો $\alpha ,\,\beta ,\,\gamma \in \,\left( {0,\,\frac{\pi }{2}} \right)$, તો $\frac{{\sin \,(\alpha + \beta + \gamma )}}{{\sin \alpha + \sin \beta + \sin \gamma }}  = . . ..$

 $\frac{{3 + \cot {{76}^o}\cot {{16}^o}}}{{\cot {{76}^o} + \cot {{16}^o}}}$ =