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3 and 4 .Determinants and Matrices
medium
The value of $k \in R$, for which the following system of linear equations
$3 x-y+4 z=3$
$x+2 y-3 x=-2$
$6 x+5 y+k z=-3$
has infinitely many solutions, is:
A
$3$
B
$-3$
C
$5$
D
$-5$
(JEE MAIN-2021)
Solution
$\left|\begin{array}{ccc}3 & -1 & 4 \\ 1 & 2 & -3 \\ 6 & 5 & K\end{array}\right|=0$
$\Rightarrow 3(2 \mathrm{~K}+15)+\mathrm{K}+18-28=0$
$\Rightarrow 7 \mathrm{~K}+35=0 \Rightarrow \mathrm{K}-5$
Standard 12
Mathematics
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