{log _3},4{log _4},5{log _5},6{log _6},7{log | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) ${\log _3}4.{\log _4}5.{\log _5}6.{\log _6}7.{\log _7}8.{\log _8}9$

$ = {{\log 4} \over {\log 3}}.{{\log 5} \over {\log 4}}.{{\log 6} \over {\l

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(b) ${\log _3}4.{\log _4}5.{\log _5}6.{\log _6}7.{\log _7}8.{\log _8}9$

$ = {{\log 4} \over {\log 3}}.{{\log 5} \over {\log 4}}.{{\log 6} \over {\log 5}}.{{\log 7} \over {\log 6}}.{{\log 8} \over {\log 7}}.{{\log 9} \over {\log 8}} = {{\log 9} \over {\log 3}}$

$ = {\log _3}9 = {\log _3}{3^2} = 2$.

${\log _3}\,4{\log _4}\,5{\log _5}\,6{\log _6}\,7{\log _7}\,8{\log _8}\,9= . .$ . .

Similar Questions

${2^{{{\log }_{\sqrt 2 }}(x - 1)}} > x + 5$ નું સમાધાન કરે તેવી $x$ ની વાસ્તવિક કિમતોનો ગણ મેળવો.

$7\log \left( {{{16} \over {15}}} \right) + 5\log \left( {{{25} \over {24}}} \right) + 3\log \left( {{{81} \over {80}}} \right)= . . . .$

${(0.05)^{{{\log }_{_{\sqrt {20} }}}(0.1 + 0.01 + 0.001 + ......)}}= . .$ . .

જો $A = {\log _2}{\log _2}{\log _4}256 + 2{\log _{\sqrt 2 \,}}\,2$ તો $A = . . . .$

જો ${\log _k}x.\,{\log _5}k = {\log _x}5,k \ne 1,k > 0$ તો $x = . . . .$