If $a, b, c$ are all different from zero and $\left| {\begin{array}{*{20}{c}} {1  + a}&1&1\\ 1&{1  +  b}&1\\ 1&1&{1  +  c} \end{array}} \right| = 0$ , then the value of $a^{-1} + b^{-1} + c^{-1}$ is

Let $a-2 b+c=1$

If $f(x)=\left|\begin{array}{lll}{x+a} & {x+2} & {x+1} \\ {x+b} & {x+3} & {x+2} \\ {x+c} & {x+4} & {x+3}\end{array}\right|,$ then

Using properties of determinants, prove that:

$\left| {\begin{array}{*{20}{l}}
  {\sin \alpha }&{\cos \alpha }&{\cos (\alpha  + \delta )} \\ 
  {\sin \beta }&{\cos \beta }&{\cos (\beta  + \delta )} \\ 
  {\sin \gamma }&{\cos \gamma }&{\cos (\gamma  + \delta )} 
\end{array}} \right| = 0$

By using properties of determinants, show that:

$\left|\begin{array}{ccc}x+y+2 z & x & y \\ z & y+z+2 x & y \\ z & x & z+x+2 y\end{array}\right|=2(x+y+z)^{3}$

Evaluate $\left|\begin{array}{ccc}102 & 18 & 36 \\ 1 & 3 & 4 \\ 17 & 3 & 6\end{array}\right|$