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3 and 4 .Determinants and Matrices
easy
$\left| {\,\begin{array}{*{20}{c}}{441}&{442}&{443}\\{445}&{446}&{447}\\{449}&{450}&{451}\end{array}\,} \right|$
A
$441 × 446 × 451$
B
$0$
C
$-1$
D
$1$
Solution
(b) $\left| {\,\begin{array}{*{20}{c}}{441}&{442}&{443}\\{445}&{446}&{447}\\{449}&{450}&{451}\end{array}\,} \right|$ = $\left| {\,\begin{array}{*{20}{c}}
{ – 1}&{ – 1}&{443} \\
{ – 1}&{ – 1}&{447} \\
{ – 1}&{ – 1}&{451}
\end{array}\,} \right|$ = 0
$\left\{ {{C_1} \to {C_1} – {C_2},\,{C_2} \to {C_2} – {C_3}} \right\}$
Standard 12
Mathematics