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10-1.Circle and System of Circles
easy
The value of $c$, for which the line $y = 2x + c$ is a tangent to the circle ${x^2} + {y^2} = 16$, is
A
$ - 16\sqrt 5 $
B
$20$
C
$4\sqrt 5 $
D
$16\sqrt 5 $
Solution
(c) From $c = \pm a\sqrt {1 + {m^2}} $,
Here, $a = 4,\,m = 2$
$\therefore \,c = \pm 4\sqrt {1 + 4}$
$= \pm 4\sqrt 5 $.
Standard 11
Mathematics
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