Gujarati
10-1.Circle and System of Circles
easy

The value of $c$, for which the line $y = 2x + c$ is a tangent to the circle ${x^2} + {y^2} = 16$, is

A

$ - 16\sqrt 5 $

B

$20$

C

$4\sqrt 5 $

D

$16\sqrt 5 $

Solution

(c) From $c = \pm a\sqrt {1 + {m^2}} $,

Here, $a = 4,\,m = 2$

$\therefore \,c = \pm 4\sqrt {1 + 4}$

$= \pm 4\sqrt 5 $.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.