- Home
- Standard 12
- Physics
1. Electric Charges and Fields
easy
મુક્ત અવકાશમાં વિદ્યુત પરમિટિવિટિ નું મૂલ્ય ........ છે.
A
$9 \times {10^9}\,N{C^2}/{m^2}$
B
$8.85 \times {10^{ - 12}}\,N{m^2}/{C^2}sec$
C
$8.85 \times {10^{ - 12}}\,{C^2}/N{m^2}$
D
$9 \times {10^9}\,{C^2}/N{m^2}$
Solution
From $F=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{ I ^2}$
If Force, $F=1 N$
charge, $q=1 C$
distance, $r=1 m$
Then, $q_0=\frac{q^2}{F \times 4 \pi \times r^2}$
$=\frac{(1)^2}{1 N \times 4 \times 3.14 \times(1 m )^2}$
$\varepsilon_0=8.854 \times 10^{-12} \frac{ C ^2}{ Nm ^2}$
Standard 12
Physics
