From graph, initial velocity $=v_{0}$ and distance travelled in time $t=x_{0}$.

For the graph $\tan \theta=\frac{v_{0}}{x_{0}}=\frac{v_{0}-v}{x} \quad \ldots$ (1)

Where, $v$ is velocity and $x$ is displacement at any instant of time $t$.

From Eq. (i) $\quad v_{0}-v=\frac{v_{0}}{x_{0}} x$ $\Rightarrow \quad v=\frac{-v_{0}}{x_{0}} x+v_{0} \ldots$

$(2)$ We know that

Acceleration $a=\frac{d v}{d t}=\frac{-v_{0}}{x_{0}} \frac{d x}{d t}+0$

$a=\frac{-v_{0}}{-}(v)$

$=\frac{x_{0}}{x_{0}}\left(\frac{-v_{0}}{x_{0}} x+v_{0}\right)$

$=\frac{v_{0}^{2}}{x_{0}^{2}} x-\frac{v_{0}^{2}}{x_{0}}$

$(\because$ From $(2))$

Graph of a versus $x$ is given above.