The voltage of an ac source varies with time according to the equation $V = 100\sin \;100\pi t\,\cos \,100\pi t$ where $t$ is in seconds and $V$ is in volts. Then
The voltage of an ac source varies with time according to the equation $V = 100\sin \;100\pi t\,\cos \,100\pi t$ where $t$ is in seconds and $V$ is in volts. Then
- A
The peak voltage of the source is $100$ volts
- B
The peak voltage of the source is $50$ volts
- C
The peak voltage of the source is $100/\sqrt 2 $ volts
- D
The frequency of the source is $50\, Hz$
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