Young's modulus of a rubber string 8, cm long and density 1.5,kg/{m^3} is 5 × {10^8},N/{m^2} ,

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8.Mechanical Properties of Solids

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The Young's modulus of a rubber string $8\, cm$ long and density $1.5\,kg/{m^3}$ is $5 \times {10^8}\,N/{m^2}$, is suspended on the ceiling in a room. The increase in length due to its own weight will be

A

$9.6 \times {10^{ - 5}}\,m$

B

$9.6 \times {10^{ - 11}}\,m$

C

$9.6 \times {10^{ - 3}}\,m$

D

$9.6\, m$

(AIIMS-1986)

Solution

(b)$l = \frac{{{L^2}dg}}{{2Y}} = \frac{{{{(8 \times {{10}^{ – 2}})}^2} \times 1.5 \times 9.8}}{{2 \times 5 \times {{10}^8}}}$

$ = 9.6 \times {10^{ – 11}}m$

Standard 11

Physics

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