- Home
- Standard 11
- Mathematics
6.Permutation and Combination
easy
There are $9$ chairs in a room on which $6$ persons are to be seated, out of which one is guest with one specific chair. In how many ways they can sit
A
$6720$
B
$60480$
C
$30$
D
$346$
Solution
(a) $5$ persons are to be seated on $8$ chairs $i.e.$ $^8{C_3} \times 5\;!$ or $6720$.
{Since $5$ chairs can be select in $^8{C_5}$ and then $5$ persons can be arranged in $5\;!$ ways}.
Standard 11
Mathematics
