6.Permutation and Combination
medium

If $^n{C_{r - 1}} = 36,{\;^n}{C_r} = 84$ and $^n{C_{r + 1}} = 126$, then the value of $r$ is

A

$1$

B

$2$

C

$3$

D

None of these

(IIT-1979)

Solution

(c) Here $\frac{{^n{C_{r – 1}}}}{{^n{C_r}}}$ = $\frac{{36}}{{84}}$ and $\frac{{^n{C_r}}}{{^n{C_{r + 1}}}} = \frac{{84}}{{126}}$.

==> $3n – 10r = – 3$ and $4n – 10r = 6$

On solving, we get $n = 9$,$r = 3$.

Standard 11
Mathematics

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